我正在处理C#中的XML文件。
我想翻一番,做一些插手。
我的xml档案就是这样。
<Content xmlns="http://ABCD.com/sdltridion/schemas/XXXXX">
<first>ABCD</first>
<second>DCEF</second>
</Content>
我想从根tag中抽出Xml的名字空间,ang升到XX。
所需产出:XXXXX
任何人都可以为此提供帮助。
谢谢。
引证:
var xdoc = XDocument.Parse(xml);
var ns = xdoc.Root.Name.Namespace.NamespaceName;
var value = new Uri(ns).Segments.LastOrDefault();
您可以尝试XNamespace。
XNamespace ns = XNamespace.Get("http://ABCD.com/sdltridion/schemas/XXXXX");
var result = XElement.Load("URL").Descendants(ns + "NODENAME");
成就
Deepu
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