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XDocuments 获得根基辅助价值
原标题:XDocument getting Root Attributes values

如何利用XDocument在数据表中从标题1中获取价值

<Person ActionType = "Update"  Title1="Miss" />

我审判了后代、XAttributes和各种东西...... 可能的投入是错误的,但

XDocument xml = XDocument.Parse(row["XMLTransaction"].ToString());

IEnumerable<XAttribute> query =
from transaction in xml.Root.Elements()
select transaction.Attribute(attribute);
最佳回答

如果该指示是您的字面XML,那么你就应当删除<条码>。

更不用说XElement,而不是XDocument:

 var xml = XElement.Parse(row["XMLTransaction"].ToString());

 IEnumerable<XAttribute> query = xml.Attributes();
问题回答

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