Question

this would be my string

Panipat,Patna,

结果应为Panipat,Patna。

,Panipat,Patna,

结果应为Panipat,Patna。

Panipat,

结果应为<>Panipat。

,Panipat,

结果应为<>Panipat。

如何做到这一点。需要帮助!

Answer 1

请参看<代码>。 Trim功能

Dim result = input.Trim(New Char() { ","c })

这一职能将消除从显示价值开始和结束之时起所有具体性质的事件。

例假

Dim str As String = "hello,"
Dim res = str.Trim(New Char() {","c})
Console.WriteLine(res)  Prints: hello

Answer 2

http://www.dotnetperls.com/replace-vbnet”rel=“nofollow”>。

Function RemoveCharacter(ByVal stringToCleanUp, ByVal characterToRemove)
   Return stringToCleanUp.Replace(characterToRemove, "")
End Function

为此:

Private Sub Main()
    Dim inputText As String = "This is string ending with comma character,"

    Dim result As String = inputText.Trim(",".ToCharArray())

    Console.WriteLine(result)

End Sub

Answer 3

实现您目标的最佳途径是定期表达。下面的例子将适时使用两个术语。

e.g 替换Panipat,Patna,改为Panipat,Patna

Public Function Return_Strip_Word(Text As String) As String
    Dim reg As String = "(?<stripword>(w+),(w+))"
    Dim VDMatch As System.Text.RegularExpressions.Match = System.Text.RegularExpressions.Regex.Match(Text, reg)
    If VDMatch.Success Then
         Return VDMatch.Groups("stripword").Value
    Else
        Return Text
    End If
End Function

友情链接