i)有<代码>List<List<Person>> i 想要在以前的收件中复制所有人: List<Person> Collection。
i)
var People = new List<List<Person>>{ new List<Person>{...},... };
var people = new List<Person>();
People.ForEach(q => people.AddRange(q.People));
return people;
是否有更好的办法这样做?
var allPersons = People.SelectMany(p => p);
您应使用SelectMany。 推广方法:
var people = People.SelectMany(p => p)
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