Question

在 Java文中获得时间

var ts = new Date().getTime()

迄今为止,我使用了以下代码:

>>> jsts = 1335205804950
>>> dt = datetime.datetime.fromtimestamp(jsts/1000)
>>> dt
datetime.datetime(2012, 4, 24, 0, 30, 4)

I divide timestamp by 1000 because I get error like

ValueError                                Traceback (most recent call last)
1 d = datetime.datetime.fromtimestamp(a)
ValueError: year is out of range

Answer 1

现行方法是正确的,必须按1,000条加以区别,因为 your将时间序列放在微秒中,而<代码>日。

为了保持微秒的精确度,你可以通过1000.0加以区别,因此,你正在使用浮动的划分而不是分类:

>>> dt = datetime.datetime.fromtimestamp(jsts/1000.0)
>>> dt
datetime.datetime(2012, 4, 23, 11, 30, 4, 950000)

Answer 2

由于回答的@andrew-clark,我有同样的问题,一夫树立了处理这两个案件的小榜样:

     try:
        # when timestamp is in seconds
        date = datetime.fromtimestamp(timestamp)
    except (ValueError):
        # when timestamp is in miliseconds
        date = datetime.fromtimestamp(timestamp / 1000)

Answer 3

还有一些错误: 我有一个类似的问题,但是,不准确的时间出现在微观轨道上,即,我不得不将时间长度隔100 000,以取得正确的结果。

dt = datetime.datetime.fromtimestamp(1502360499615921)

Answer 4

The way you do it is the correct way, because js includes milliseconds in the date/time. Python (and PHP) as far as I know, don t. For more precision you could use /1000.0.

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