Question

我对我经常表达方式感到困惑。我以前想要的是,用户不希望进入的最大数字是3,数字不应从零开始。数位数在位数之前,即三位数或两位数或一位数,但不能从零开始。我想让用户在奇马尔点之后进入一位数,这不应超过一位数。因此,这些模式是什么?

例:

<Number允许进入:1.3,22.3,333.4,999.6

<>0> 不允许进入:0,0.1,.1,444444.67,333.78

www.un.org/spanish/ecosoc 《刑法》第一版

tempEditText.setFilters(new InputFilter[]{new DecimalDigitsInputFilter(3,1)});
class DecimalDigitsInputFilter implements InputFilter
{
    Pattern mPattern;

    public DecimalDigitsInputFilter(int digitsBeforeZero, int digitsAfterZero)
    {
        mPattern = Pattern.compile("[0-9]{0," + (digitsBeforeZero - 1) + "}+((\.[0-9]{0," + (digitsAfterZero - 1) + "})?)");
    }
    
    @Override
    public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend)
    {
        Matcher matcher = mPattern.matcher(dest);
        if(!matcher.matches())
        {
            return "";
        }
        return null;
    }
}

Answer 1

我认为,你想要的模式是:

^[1-9]d{0,2}.d?$

解释:

^        // Start of string
[1-9]    // First digit can t be 0
d{0,2}  // Zero, one, or two more digits after first digit
.       // Literal decimal point
d?      // Optional single digit after decimal point
$        // End of string

在你的法典中:

mPattern = Pattern.compile("^[1-9]\d{0," + (digitsBeforeZero - 1)
           + "}(\.\d{0," + digitsAfterZero + "})?$");

你的亲子点和挂号位数表示,像“1”这样的数字不匹配。这里的版本要求删除点,随后的数位数可选择:

mPattern = Pattern.compile("^[1-9]\d{0," + (digitsBeforeZero - 1)
           + "}\.\d{0," + digitsAfterZero + "}?$");

Answer 2

Pattern.compile("[1-9]{0," + (digitsBeforeZero - 1) + "}+((\.[0-9]{0," + (digitsAfterZero - 1) + "})?)"

......

Answer 3

你有以下问题:

"[0-9]{0," + (digitsBeforeZero - 1) + "}+((\.[0-9]{0," + (digitsAfterZero - 1) + "})?)"
 ^^^^^                                              ^
  1                                                 2

你的模式从一开始就允许0,但你不希望领导0。
你允许在 do子之后有0位数,但你不想。
你们需要紧靠你们的reg,以避免部分相匹配(允许允许“Foo123.4Bar”)

因此,

mPattern = Pattern.compile("^[1-9][0-9]{0," + (digitsBeforeZero - 1) + "}((\.[0-9]{1," + (digitsAfterZero - 1) + "})?)$");
                                                                                                          ^^^^
                                                                                                       really -1 ???

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