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Closed 9 years ago.

这是我拥有的:

class Person {
  Integer id;
  String name;
}

// A list of persons:
List<Person> persons

// Now I have something like this:
List<Integer> ids  // where the ids are stored in an specific order

Basically I wanna sort the persons list in the same order like the ids.

难道有更好的方式使用像两种假肢,并创造新的个人-文化?

regards && tia

页: 1

Answer 1

http://www.un.org。参比者获得被比较者的遗嘱,并在子女名单中按顺序排列:

List<Person> persons = ...;
final List<Integer> ids = ...;

Collections.sort(persons, new Comparator<Person>() {
    @Override
    public int compare(Person p1, Person p2) {
        int index1 = ids.indexOf(p1.getId());
        int index2 = ids.indexOf(p2.getId());
        return index1 < index2 ? -1 : (index1 == index2 ? 0 : 1);
    }
});

Note: this code assumes that the ids of all persons in the list will appear in the ids list.

Answer 2

Map each of the ids into its index: Map<Integer, Integer> idToIndex;
Run the following loop.

for (int i = 0, size = persons.length - 1; i < size; ++i) {
  var targetIndex = idToIndex.get(persons.get(i).id);
  if (targetIndex != i) {
    persons[i] <-> persons[targetIndex];
  }
}

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