Question

I have word frequencies observed in a data corpus in a single day, across 10minutes time interval. The data looks something like this:

word 00:00:00 00:11:00 00:22:00 00:33:00 . . . .  23:17:00 23:28:00 23:39:00
Robert  10       20        22       32   . . . .   10        11        10
Harvey  12       35        12       12   . . . .   15        26        9

I want to generate a time series object for this data using R. I know that the ts() function can be used to generate time series object where I can specify the start year and the time-interval being months or quarters. Example:

ts(data, frequency=12, start=c(1946,1))

但是,我不知道我如何利用ts来说明在一天10分钟内收集的数据。任何cl?

Also, as you can see my data has time information in the header. Can that be used to generate time series object in R?

Answer 1

简言之,你的主要选择是:

使用<代码>(),但读到帮助页数,显示您可使用fpot=ordeltat=。由于你的数据频率事实上是固定的,你可以尝试像<代码>deltat=24*60/11这样的东西。查阅您的数据看来是11分钟,而不是10分钟。
Use the zoo 页: 1 我发现zoo更便于与外界合作。

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