Question

I am using imaplib module for connecting to Gmail Imap, and i am getting the below mentioned error. I am using select command to connect

Labelname is  **LabelName

I Get this Error:

    resp, data = self._imap.select("**LabelName")
  File "/usr/lib/python2.6/imaplib.py", line 642, in select
    typ, dat = self._simple_command(name, mailbox)
  File "/usr/lib/python2.6/imaplib.py", line 1060, in _simple_command
    return self._command_complete(name, self._command(name, *args))
  File "/usr/lib/python2.6/imaplib.py", line 895, in _command_complete
    raise self.error( %s command error: %s %s  % (name, typ, data))
imaplib.error: SELECT command error: BAD [ Could not parse command ]

而如果名称为“Label”

** LabelName

它成功地连接起来。

谁能告诉我这里正在发生什么?

Answer 1

图一问题,在利用微粒连接的同时,我们需要将:

imapobj.select( " +  **Foldername  +  " )

类似情况

"**Foldername"

友情链接