我有一系列具体的日期,格式为<编码>d/mm/yyyyyy。
我想按月和逐年按摩擦地确定日期,但我不知道,因为最终会根据月数最多的计算。
for example i have the following array: 16/04/2012 01/05/2013 01/02/2012 10/11/2012 01/12/2012
normally the result after the sort is: 01/02/2012 16/04/2012 01/05/2013 10/11/2012 01/12/2012
while what i want is: 01/02/2012 16/04/2012 10/11/2012 01/12/2012 01/05/2013 year 2012 first then 2013
i n t使该代码作了改动,因为我不知道算法是如何运作的,而且我不得不使用,只有1 radix 。
不要把日期划分在你们的代表权上,而是以单独的方式来考虑。 例如,在01/02/2012年这一天,形成了一种关键的20120201。 现在,两位数的顺序从最多到最不重要,你可以将关键数作为数字处理,并将之分应用于这些数字。
If you wish, you don t have to explicitly create the sort keys, but then you d have to modify the code that picks a digit for a round of radix sort to enforce proper order.
你们需要两次使用混合体,首先是在本月,然后是当年。 如果你只使用rad,那么你就不得不在这一年进行分类,那么,同年之内的几个月不会被命令。 也许你可以在一年内对数月采用不同的算法,或者根本不使用混合法。 是否有特别原因,为什么你只能一度?
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