Question

I want to find a way to get all the sub-elements of an element tree like the way ElementTree.getchildren() does, since getchildren() is deprecated since Python version 2.7.
I don t want to use it anymore, though I can still use it currently.

Answer 1

http://www.un.org/Depts/DGACM/index_french.htm

all_descendants = list(elem.iter())

更完整的实例:

>>> import xml.etree.ElementTree as ET
>>> a = ET.Element( a )
>>> b = ET.SubElement(a,  b )
>>> c = ET.SubElement(a,  c )
>>> d = ET.SubElement(a,  d )
>>> e = ET.SubElement(b,  e )
>>> f = ET.SubElement(d,  f )
>>> g = ET.SubElement(d,  g )
>>> [elem.tag for elem in a.iter()]
[ a ,  b ,  e ,  c ,  d ,  f ,  g ]

排除根基:

>>> [elem.tag for elem in a.iter() if elem is not a]
[ b ,  e ,  c ,  d ,  f ,  g ]

Answer 2

in the pydoc it is mentioned to use list() method over the node to get child elements.
list(elem)

Answer 3

如果你想要获得所有要素,你可以使用:

a_lst = list(elem.iter( a ))

如果<条码>elem也包括在内。

Answer 4

现有的答案都不会找到所有儿童。这一解决办法使用美容,而不是“ETree”,但将发现所有儿童,而不是顶级:

from bs4 import BeautifulSoup    

with open(filename) as f:
    soup = BeautifulSoup(f,  xml )

results = soup.find_all( element_name )

Answer 5

也许这不符合《任择议定书》的实际问题,但从广义上讲,我建议,如果有人想获得以某种名称命名的所有要素,例如物体,则可以使用(一种替代方法:@Turstles 至少对我来说似乎更自然的是:

objs = tree.findall( object )

这份清单还列有一份清单。

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