我的<代码>bash_Functions界定了以下两项职能: (载于.bashrc):
up() {
if (($# == 0)); then
cd ..
else
for basename; do
local result=$(_foo)
echo $result
cd $result
done
fi
}
_foo() {
echo ${PWD%/$1/*}/$basename
}
虽然我可以执行<条码>_foo,在一执行<条码>时,看上去看<条码>_foo。 我在这里做过错,还是不可能这样做?
它的确是“know”_foo,但你没有通过一个参数来_foo,这样可能造成混乱。
Bash 字母顺序先后执行。 在您的情形下,_foo(>>可在up(>前界定,一切工作均应处以罚款。
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