Question

In my program I am printing float numbers to file. There is high precision of these numbers so there are many digits after decimal point, i.e number 0.0433896882981. How can I reduce number of digits that I print into file? So I would print, say, 0.043 instead of 0.0433896882981.

Answer 1

你们可以采用基本的形式,例如:

>>> print  %.4f  % (2.2352341234)
2.2352

Here, the %.4f tells Python to limit the precision to four decimal places.

Answer 2

You don t say which version, or really how you are doing it in, so I m going to assume 3.x.

str.format("{0:.3f}", pi) # use 3 digits of precision and float-formatting.

具体做法一般认为:

[[填满]

其他例子:

>>> str.format("{0:" ">10.5f}", 3.14159265)
    3.14159 
>>> str.format("{0:0>10.5f}", 3.14159265)
 0003.14159 
>>> str.format("{0:<10.5f}", 3.14159265)
 3.14159

Answer 3

digit点后数位数可按以下格式说明:

In [15]: n = 0.0433896882981
In [16]: print  %.3f  % n

(a) 生产:

0.043

<代码>% f部分表示,你正在印刷若干个数字,点数为点数,.3。

其他例子:

In [17]: print  %.1f  % n
0.0

In [18]: print  %.2f  % n
0.04

In [19]: print  %.4f  % n
0.0434

In [20]: print  %.5f  % n
0.04339

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