Question

def percent(marks):
    return (marks[0]+marks[1]+marks[2]+marks[3]/400)*100

    marks1=[54,65,85,54]
    percent1=percent(marks1)

    marks2=[54,52,65,85]
    percent2 = percent(marks2)
    print(percent1,percent2)

Answer 1

<代码>return之后的线路不会在任何时候执行。因此,你可以删除这些内容,任何事情都不会改变。该信息告诉你,因为制定这种法典非常罕见。

我认为你希望:

def percent(marks):
    return (marks[0]+marks[1]+marks[2]+marks[3]/400)*100

marks1 = [54, 65, 85, 54]
percent1 = percent(marks1)

marks2 = [54, 52, 65, 85]
percent2 = percent(marks2)
print(percent1, percent2)

9. 灰色代码中的空间。在你的法典中,所有内容都是这一职能的一部分。在固定代码中,它们不是。

Answer 2

    "[python]": {
        "editor.showUnused": false,
    },

Answer 3

i know why code is unreachable its because the interpreter thinks your program has closed. Something like exit() what is under exit() the code interpreter thinks cannot be executed, But it can be executed!

Answer 4

就在I m而不是最后一点知道的情况下,其功能是返回类型 hint ->打字。 NoReturn will causes is unachable press in callser, use None.

NoReturn vs 无

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