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Closed 11 years ago.

我有这样的档案:

Name Position Letter String
Bla 123 A ..B.,,,.C..
Bla 123 B ..a.,,,.C..
Bla 123 C ..b.,,,.A..

我愿将<代码>>和>>、改为(在第1行,<代码>A。

最终产品:

Name Position Letter String
Bla 123 A AABAAAAACAA
Bla 123 B BBaBBBBBCBB
Bla 123 C CCbCCCCCACC

The awk thinking is replace character in column 4 with "the" character in column 3. I think awk should be the correct tool for this but I´m stuck with replacing character in string.

sed s/(^.{4})./{3}/ don t work and I considered may be the wrong tool.

Awk/sed/python/perl/vi Solutions受到欢迎。

Answer 1

perl -pale  $F[3]=~s/[.,]/$F[2]/g;$_=join" ",@F  file

>>>>,<>,见。

Answer 2

不用使用<条码>的常规表述的解决办法:

   with open( in.txt ) as f:
        for x in f:
            x=x.rstrip().split()
            x[-1]=x[-1].replace( . ,x[-2])
            x[-1]=x[-1].replace( , ,x[-2])
            print(" ".join(x))

    Name Position Letter String
    Bla 123 A AABAAAAACAA
    Bla 123 B BBaBBBBBCBB
    Bla 123 C CCbCCCCCACC

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