I need some help creating a regular expression.
I need to get all the words between the first keyword and the last keyword.
第一关键词为<代码>。 所有和最后关键词为<代码>。 见。
抽样投入:
a. 所有bc、b、c、d
产出必须:
abc abc abcd
这是我目前的reg:
(\s*All (\w|\s)+( At))
我的问题是,如果这种投入一样:
a. 全部b
产出如下:
ab
2. 对中文本不作改动:
(s*All (w|s)+?( At))
注 添加<代码>?。 这应当告诉列车发动机返回<代码>(<>>>>>(>>>>+部分最短的配方,希望能产生您所需要的结果。
阁下 努力:
String toSearchFor = source.substring (source.indexOf ("All"), source.indexOf ("At")+"At".length);
然而,我不敢肯定与什么有关。
"At At All abc At All def All ghi At jkl At At All"
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