Question

目前有3个数学单元:交叉、差异和结合(统一)。在PHP中,我们能够以阵列开展这一行动:

intersection: array_intersect
difference: array_diff

www.un.org/spanish/ecosoc 工会的职能是什么?

结果阵列中不得有重复(如array_intersection和-array_diff)。

如果指数为数字,则array_joint http://www.php.net/manual/en/Function.array-joint.php“rel=“noretinger”>PHP docs。

Answer 1

Try array_joint:

array_unique(array_merge($array1, $array2));

PHP Manual

Answer 2

array_unique(阵列_joint(......)>

Answer 3

被告方的回答是,从两个按顺序编号的阵列中得出一定数量的阵列——这里有一些选择,可以:

array_values(array_unique(array_merge($array1, $array2)));

(Adrien的答复,后重编钥匙)

array_keys(array_flip($array1)+array_flip($array2))

(确定钥匙中的数值,并使用阵列工会经营者)

array_merge($array1, array_diff($array2, $array1))

(Remove the shared values from the second array before merging)

Benchmark results (for merging two arrays of length 1000 a thousand times on my system):

Unique (Adrien s version): 2.862163066864 seconds
Values_Unique: 3.12 seconds
Keys_Flip: 2.34 seconds
Merge_Diff: 2.64 seconds

抽样测试,但两种阵列非常相似(至少80%重复):

Unique (Adrien s version): 2.92 seconds
Values_Unique: 3.15 seconds
Keys_Flip: 1.84 seconds
Merge_Diff: 2.36 seconds

It seems using the array union operator to do the actual union is the fastest method. Note however that array_flip is only safe if the array s values are all strings or all integers; if you have to produce the union of an array of objects, I recommend the version with array_merge and array_diff.

Answer 4

利用“+”经营者这样做。 See thelink Arrayworktors

Answer 5

http://www.unique

Answer 6

http://php.net/manual/en/language.operators.array.php rel=“nofollow noreferer”>。 PHP: ArrayOperationtors 文件:

<?php
$a = array("a" => "apple", "b" => "banana");
$b = array("a" => "pear", "b" => "strawberry", "c" => "cherry");

$c = $a + $b; // Union of $a and $b
echo "Union of $a and $b: 
";
var_dump($c);

$c = $b + $a; // Union of $b and $a
echo "Union of $b and $a: 
";
var_dump($c);
?>

如执行,该书将打印如下:

Union of $a and $b:
array(3) {
  ["a"]=>
  string(5) "apple"
  ["b"]=>
  string(6) "banana"
  ["c"]=>
  string(6) "cherry"
}
Union of $b and $a:
array(3) {
  ["a"]=>
  string(4) "pear"
  ["b"]=>
  string(10) "strawberry"
  ["c"]=>
  string(6) "cherry"
}

Answer 7

OP没有具体说明该联盟是按 值/strong>,还是通过key,而PHP则有,即合并价值和+合并钥匙。成果取决于阵列是否是指数化还是主要为和,这些阵列首先出现。

$a = [ a , b ]; $b = [ b , c ]; $c = [ a => A , b => B ]; ‌‌$d = [ a => AA , c => C ]; Indexed array 见array_joint。 By value using array_merge ‌‌array_merge($a, $b); // [‌0 => a , 1 => b , 2 => b , 3 => c ] ‌‌array_merge($b, $a); // ‌[0 => b , 1 => c , 2 => a , 3 => b ] merge by key using + operator 见营运人。 ‌‌$a + $b; ‌// [0 => a , 1 => b ] $b + $a; // [0 => b , 1 => c ] Keyed array By value using array_merge ‌array_merge($c, $d); // ‌[ a => AA , b => B , c => C ] array_merge($d, $c); // [ a => A , c => C , b => B ] merge by key using + operator $c + $d; // [‌ a => A , b => B , c => C ] ‌‌$d + $c; // ‌[ a => AA , c => C , b => B ]

Answer 8

<代码>+的操作者:

$x[0] = 4;
$x[1] = 1;

$y[0] = 9;
$y[2] = 5;

$u = $y + $x;

// Results in:
$u[0] === 9;
$u[1] === 1;
$u[2] === 5;

注:$x +$y!=$y +$x

Answer 9

$result = array_merge_recursive($first, $second);

如果你有内部阵列阵列,则可能有用。

Answer 10

Just use $array1 + $array2 It will result union of both array.

Answer 11

引证:

function array_union($array1, $array2){
    return array_unique(array_merge($array1, $array2));
}

Indexed array

By value using `array_merge`

merge by key using `+` operator

Keyed array

By value using `array_merge`

merge by key using `+` operator

友情链接