Question

import re
line = "the heart was made to be broken"
line_split2 = re.split(r [ 	

, ]+ ,line)

def chunks(line_split2, n):
    for i in xrange(0, len(line_split2), n):
        yield line_split2[i:i+n]

separate_word = list(chunks(line_split2, 3))

import pprint
pprint.pprint(separate_word)

count = 0
for lines in separate_word:
    count = count + 1
    print count

我正试图把名单合并起来,作为判刑,并在前面显示线数。

1 the heart was
2 made to be
3 broken

Any suggest?

Answer 1

使用<代码>数字(),以跟踪以下条目:

for i, word in enumerate(separate_word, 1):
    print i,    .join(word)

> 1 the heart was
> 2 made to be
> 3 broken

Answer 2

You could use enumerate():

s = [ the heart was ,  made to be ,  broken ]

for i, line in enumerate(s, 1):
    print  %d %s  %(i, line)

1 the heart was
2 made to be
3 broken

详情见。

Answer 3

There s no need to write your own chunks function. Use the grouper recipe from the itertools documentation, then use enumerate on the result of that:

enumerate(grouper(3, line_split2), start = 1)

Here s the code for grouper:

from itertools import izip_longest

def grouper(n, iterable, fillvalue=None):
    "grouper(3,  ABCDEFG ,  x ) --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return izip_longest(fillvalue=fillvalue, *args)

Answer 4

公正使用你参加诉讼

import re
line = "the heart was made to be broken"
line_split2 = re.split(r [ 	

, ]+ ,line)

def chunks(line_split2, n):
 for i in xrange(0, len(line_split2), n):
    yield line_split2[i:i+n]

separate_word = chunks(line_split2, 3)


count = 0
for lines in separate_word:
    count = count + 1
    print count, " ".join(map(str,lines))

1 the heart was
2 made to be
3 broken

友情链接