ts = pd.Series({ a : 1, b : 2})
ids = [ a , c ] # c is not in the index
# the result I want
np.array([ts.get(k, np.nan) for k in ids])
是否有土生土路实现这一目标?
You can convert the list to Series then map the original Series
out = pd.Series(ids).map(ts).tolist()
print(out)
[1.0, nan]
或您可填充原始系列指数中的缺失值,并填写reindex。
out = ts.reindex(ids).tolist()
<代码>reindex and access to thelying numpy range:
ts.reindex(ids).values
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