Question

我是新来的,总体上说是ding。我正试图从一个文本档案中读到,每个线上都有路标。我想逐行读到文本档案线,把线体分为驾驶、行道和档案名称。

我的法典是:

import os,sys, arcpy

## Open the file with read only permit
f = open( C:/Users/visc/scratch/scratch_child/test.txt )

for line in f:
    (drive,path,file) = os.path.split(line)

    print line.strip()
    #arcpy.AddMessage (line.strip())
    print( Drive is %s Path is %s and file is %s  % (drive, path, file))

我有以下错误:

File "C:/Users/visc/scratch/simple.py", line 14, in <module>
    (drive,path,file) = os.path.split(line)
ValueError: need more than 2 values to unpack

当我只想走路和写上名字时,我不会收到这一错误。

Answer 1

页: 1 第一:

with open( C:/Users/visc/scratch/scratch_child/test.txt ) as f:
    for line in f:
        drive, path = os.path.splitdrive(line)
        path, filename = os.path.split(path)
        print( Drive is %s Path is %s and file is %s  % (drive, path, filename))

注:

the with statement makes sure the file is closed at the end of the block (files also get closed when the garbage collector eats them, but using with is generally good practice
you don t need the brackets - os.path.splitdrive(path) returns a tuple, and this will get automatically unpacked
file is the name of a class in the standard namespace and you should probably not overwrite it :)

Answer 2

你们可以使用斜体。

## Open the file with read only permit
f = open( C:/Users/visc/scratch/scratch_child/test.txt )

for line in f:
    (drive, path) = os.path.splitdrive(line)
    (path, file)  = os.path.split(path)

    print line.strip()
    print( Drive is %s Path is %s and file is %s  % (drive, path, file))

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