Question

在我的阴谋中添加一条直径,我通常使用这一代码:

ret=Rectangle((x_l[i]-dx,y_l[i]-dx),width=dx,height=dx,facecolor= red ,linestyle= solid )
ax=gca()
ax.add_patch(ret)

但我很想知道能否以不同的方式给肤色。我希望我直截了当地人听起来。我尝试对此作出更好的解释。每个休息室都是一个囚室,在每间牢房中,我界定了一个小田。我的体积范围从<代码>min_val到max_val。我想,我所推断的每个试金星都与试金星飞地的价值相对应。

Answer 1

各位用科罗拉马普计算出来的彩色添加:

import matplotlib.colorbar as cbar
import pylab as pl
import numpy as np

N = 50
xs = np.random.randint(0, 100, N)
ys = np.random.randint(0, 100, N)
ws = np.random.randint(10, 20, N)
hs = np.random.randint(10, 20, N)
vs = np.random.randn(N)
normal = pl.Normalize(vs.min(), vs.max())
colors = pl.cm.jet(normal(vs))

ax = pl.subplot(111)
for x,y,w,h,c in zip(xs,ys,ws,hs,colors):
    rect = pl.Rectangle((x,y),w,h,color=c)
    ax.add_patch(rect)

cax, _ = cbar.make_axes(ax) 
cb2 = cbar.ColorbarBase(cax, cmap=pl.cm.jet,norm=normal) 

ax.set_xlim(0,120)
ax.set_ylim(0,120)
pl.show()

Answer 2

调整南半球的答案,提供不依靠皮拉布的解决办法:

import matplotlib.pyplot as plt
import matplotlib.patches as patches
import numpy as np
import matplotlib.colorbar as cbar

fig,ax=plt.subplots(1)

rng=6
plt.ylim(0,rng)
plt.xlim(0,rng)

N = 30
x = np.random.rand(N)*rng
y = np.random.rand(N)*rng
colors=np.random.rand(N)
normal = plt.Normalize(0,1) # my numbers from 0-1

cmap=plt.cm.RdYlBu_r
c=cmap(colors)

for i in range(N):
    val=0.5
    rect=patches.Rectangle((x[i],y[i]),0.3,0.3,
                            edgecolor= black ,
                            linewidth = 1,
                            facecolor = c[i],
                            ) 
    ax.add_patch(rect)

cax, _ = cbar.make_axes(ax) 
cb2 = cbar.ColorbarBase(cax, cmap=cmap,norm=normal) 

plt.savefig("test.png")

下面图表:

友情链接