Question

def calculate_average(numbers):
    total = sum(numbers)
    average = total / len(numbers)
    return average
    
print(average)
calculate_average([34, 30, 12])

Output shows that average is not defined which I dont understand why. Can someone explain why to me? I already know I can use this line print(calculate_average([34, 30, 12])) to print out. But I want to know why my code is not working. I understand return will pass the data outside of the function and end the function, but I dont understand how to print it out as output. Please write down the corrected version and explain me to me. Thank you so much.

I try to use python tutor and also ask chatgpt but still dont understand why or how to make it functioning.

Answer 1

贵国法典中的问题与未界定的平均变量无关,而是与你如何重新印刷结果有关。

Your function calculate_average(numbers) correctly calculates the average of a list of numbers and returns the result. In your code, you correctly call this function and store the result in the result variable:

    def calculate_average(numbers):
    total = sum(numbers)
    average = total / len(numbers)
    return average
    
result = calculate_average([34, 30, 12])
print(result)

Answer 2

既然你的工作恢复平均价值,你可以做到:

print(calculate_average([34, 30, 12]))

答复部分已经回答了这个问题。

或确定新的全球平均变量并分配其功能价值:

average = calculate_average([34, 30, 12])
print(average)

Answer 3

Your problem is with this line, as the variable average is not defined within global scope:

print(average)

http://www.w3schools.com/python/python_cop.asp”rel=“nofollow noreferer”>W3Schools:

只能从区域内部产生一个变数。网址:http://strong>。

一项职能中产生的变数属于该职能中的“地方范围:>,只能在该职能范围内使用。

您正在试图从全球范围<>/em>上打印可变的<代码>平均。

Instead, you could define the variable average in global scope from the return value of your function

average = calculate_average([34, 30, 12]) print(average)

或仅直接印刷职能产出:

print(calculate_average([34, 30, 12]))

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