Question

I m running linux (Pop OS 22.04) and I m trying to make a loop using pyautgui.locateOnScreen method, here s the code:

def __clicks_print(area, *print_names, nclicks=1):
    loc = None
    while not loc:
        for print_name in print_names:
            loc = pyautogui.locateOnScreen(print_name, region=area)
            print(loc)
            if loc:
                break
    pyautogui.moveTo(loc)
    pyautogui.click(clicks=nclicks)

当我试图行使这一职能时,方案以下列错误结束:

raise ImageNotFoundException  # Raise PyAutoGUI s ImageNotFoundException.

奇怪的部分是,我使用Windows的这种准确的排位,而只是工作,方案一直寻找一个休息室,直到找到一个。

I tried to copy the exact same function I have on a Windows machine and, it doesn t work, the program keeps stopping when it fails to locate the pixels. I want the program to keep looking until it finds the pixels on the screen. This way I can give the function multiple prints to locate.

Answer 1

I managed to make it work by using a try except, so I can ignore the exception. It seems that in older pyautogui versions it was returning "None" when the image was not found and now, in more recent versions, it is throwing an excepetion. The code:

def __clicks_print(area, *print_names, nclicks=1):
    loc = None
    while not loc:
        for print_name in print_names:
            try:    
                loc = pyautogui.locateOnScreen(print_name, region=area)
                if loc:
                    break
            except:
                pass
    pyautogui.moveTo(loc)
    pyautogui.click(clicks=nclicks)

友情链接