Question

我在努力寻找一种方式,在轮式活动手递中利用功能。 Saye 我有一个纽芬兰语,在被点击时,它使用一名活动手叫OnRun。然而,用户不得不在OnRun纽顿之前点击一个电台,我想播一个电文,告诉他们要走一步。我会几次重复使用这一信息,因此,我不想照搬同一守则的复印件/剪辑,而只是要把这一信息传说成一种功能,如果用户忘记要检查一个广播局的话,就称这一信息传播功能。

如果在“谁来”活动中使用这种职能,我知道我可以简单地把这一职能当作一个论点,但我看不到我能够这样做的方式。在此提供任何帮助将受到赞赏。

Answer 1

下面的法典表明,如何形成一种微薄的方法,使你能够再利用来显示习俗的诊断,并向使用者说明他们需要接受协议。当然,你可以改变你想要做什么的条件。你们可以改变“智慧”方法,使“智商”也只改变一点点。

import wx

########################################################################
class TestFrame(wx.Frame):
    """"""

    #----------------------------------------------------------------------
    def __init__(self):
        """Constructor"""
        wx.Frame.__init__(self, None, title="Test")

        panel = wx.Panel(self)
        self.radios = wx.RadioBox(panel, label="Choices",
                                  choices = ["None", "Accept", "Reject"])

        button = wx.Button(panel, label="Run")
        button.Bind(wx.EVT_BUTTON, self.onBtn)

        sizer = wx.BoxSizer(wx.VERTICAL)
        sizer.Add(self.radios, 0, wx.ALL, 5)
        sizer.Add(button, 0, wx.ALL, 5)
        panel.SetSizer(sizer)

    #----------------------------------------------------------------------
    def onBtn(self, event):
        """"""
        btn = event.GetEventObject()
        btn.SetLabel("Running")
        radio_value = self.radios.GetStringSelection()
        if radio_value == "None":
            self.showMsg("Error", "Please Choose  Accept  or  Reject !")
        elif radio_value == "Accept":
            self.showMsg("Message", "Thank you for accepting!")
        else:
            self.showMsg("Message", "We re sorry, but you cannot continue the install")

    #----------------------------------------------------------------------
    def showMsg(self, title, msg):
        """"""
        dlg = wx.MessageDialog(None, msg, title, wx.OK | wx.ICON_QUESTION)
        dlg.ShowModal()
        dlg.Destroy()



if __name__ == "__main__":
    app = wx.App(False)
    frame = TestFrame()
    frame.Show()
    app.MainLoop()

Answer 2

I will make a stab at this, even if the answer seems too direct. I would set a property in the enclosing frame that flags whether the Radio Button has been clicked or not. Then when OnRun is called check that property. Should it be in the wrong state, call the MessageDialog and abort/pause/modify the OnRun.

http://www.ohchr.org。我这里指的是,一个有两顿的三边例子,如果不点击用户协议,这两个例子都不会导致进一步的行动。

import wx

class ButtonFrame(wx.Frame):
    def __init__(self):
        wx.Frame.__init__(self, None, -1,  Button Example , 
                          size=(300, 100))
        panel = wx.Panel(self, -1)
        self.radio = wx.RadioButton(panel, -1, "Accept user agreement", pos=(50, 10))
        self.button = wx.Button(panel, -1, "Run", pos=(50, 30))
        self.Bind(wx.EVT_BUTTON, self.OnRun, self.button)
        self.button.SetDefault()
        self.btn2 = wx.Button(panel, -1, "Walk", pos=(150, 30))
        self.Bind(wx.EVT_BUTTON, self.OnWalk, self.btn2)

    def OnRun(self, event):
        if not self.CheckRadio():
            return
        self.button.SetLabel("Running")

    def OnWalk(self, event):
        if not self.CheckRadio():
            return
        self.btn2.SetLabel("Walking")

    def CheckRadio(self):
        accepted = self.radio.GetValue()
        if not accepted:
            dlg = wx.MessageDialog(None,  First accept the user agreement ,
                                   MessageDialog , wx.OK | wx.ICON_QUESTION)
            result = dlg.ShowModal() # result not used in this demo
            dlg.Destroy()
            return False
        else:
            return True

if __name__ ==  __main__ :
    app = wx.PySimpleApp()
    frame = ButtonFrame()
    frame.Show()
    app.MainLoop()

法典从wxPython in Action改编。我希望,如果你没有在已经过去的时候解决这个问题的话,这种帮助将有所帮助。

Answer 3

您可以创建自己的信息通报,也可以使用functools.partial /lambda,向活动主管转达另外的论点:

self.Bind(wx.MY_EVENT, lambda evt: self.OnEventX(evt, handler=foo), id=12)

友情链接