Question

我有一个惯例<代码>ListView和改编者。我可以删除我的习惯名单上所列清单中的项目,但我可以删除<代码>ListView。当我试图打电话adapter.remove(position)时,编辑们说,“将一种方法“remove(int status)”。我不知道,当我把这种方法引入适应者时,我应该做些什么。法典:

www.un.org/spanish/ecosoc

lv = (ListView) findViewById(R.id.list);
        LayoutInflater mLInflater = getLayoutInflater();
        final ListViewAdapter adapter = new ListViewAdapter(
                getApplicationContext(), kimdenlist, konulist,
                mLInflater);
        lv.setAdapter(adapter);

www.un.org/spanish/ecosoc 清单:

public class ListViewAdapter extends BaseAdapter {
    static HashMap<Integer, Boolean> cartItems = new HashMap<Integer, Boolean>();
    Context mContext;
    ArrayList<String> kimdenlist; // to load images
    ArrayList<String> konulist; // for data
    LayoutInflater mLayoutInflater;

    public ListViewAdapter(Context context, ArrayList<String> kimdenlist, ArrayList<String> konulist,
            LayoutInflater layoutInflater) {
        mContext = context;
        this.kimdenlist = kimdenlist;
        this.konulist = konulist;
        mLayoutInflater = layoutInflater;
    }

    @Override
    public int getCount() 
    {

        return kimdenlist.size(); // images array length
    }

    @Override
    public Object getItem(int arg0) {

        return null;
    }

    @Override
    public long getItemId(int arg0) {

        return 0;
    }

    int count = 0;

    // customized Listview
    @Override
    public View getView(int position, View arg1, ViewGroup arg2) {

        View v;
        final int pos = position;
        v = mLayoutInflater.inflate(R.layout.listust, null);

        TextView kimden = (TextView) v.findViewById(R.id.textvKimden);
        kimden.setText(kimdenlist.get(position));
        TextView konu = (TextView) v.findViewById(R.id.textvKonu);
        konu.setText(konulist.get(position));
        CheckBox ch = (CheckBox) v.findViewById(R.id.chk);
        try {
            if (count != 0) {
                boolean b = cartItems.get(pos);
                if (b == false)
                    ch.setChecked(false);
                else
                    ch.setChecked(true);
            }
        } catch (NullPointerException e) {

        }


        ch.setOnCheckedChangeListener(new OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton arg0, boolean arg1) {
                cartItems.put(pos, arg1);
                count++;

            }
        });
        return v;
    }

    public static HashMap<Integer, Boolean> getcartItems() {
        return cartItems;
    }

}

www.un.org/spanish/ecosoc 当我点击“delete_Button”时: 我只能从名单上删除:。

konulist.remove(konulist.get(position));;
kimdenlist.remove(kimdenlist.get(position));

Answer 1

这是因为你的名单上没有删除方法! 你们延伸了基地Adapter,没有拆除方法。你的住所在名单Adapter中制造了去除方法,它会像样。

public void remove(int position){
    konulist.remove(konulist.get(position));;
    kimdenlist.remove(kimdenlist.get(position));
}

你们必须了解清单如何看待和适应工作。改编者拥有清单调查数据。当要建立名单线时,就要求采用调制方法。清单规模按适应者CapCount(......)的回报值计算。

Answer 2

从BUT NOTINSIDE ADAPTER CLASS名单上删除一个项目:

lv.removeViewAt(index);
adapter.notifyDataSetChanged();

如果“指数”具体指明了保留该项目的“名单”中的位置或指数。

To remove an item from ListView INSIDE ADAPTER CLASS: First you need to add a Tag to each item in the list. use some layout within the content item in the list to assign that Tag. This can be done within the method getView ().

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    row = convertView;

    if(row == null){
        LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        row = inflater.inflate(R.layout.item_lista_lugares_visitar, parent, false);
        holder = new ViewHolder();

        // ... DO WHAT YOU NEED HERE
        holder.linearLayoutContainer = (LinearLayout) row.findViewById(R.id.ll_container);
        // Set the position as a Tag for the view
        holder.linearLayoutContainer.setTag(position);

    } else {
        holder = (ViewHolder) row.getTag();
    }

    // ... DO WHAT YOU NEED HERE

    return row;
}

// Method for remove an item of ListView inside adapter class
// you need to pass as an argument the tag you added to the layout of your choice
public void removeView(Object position) {
      // lv and the adapter must be public-static in their Activity Class
      SomeActivity.lv.removeViewAt(Integer.parteInt(position).toString());
      SomeActivity.adapter.notifyDataSetChanged();
}

Answer 3

之后

konulist.remove(konulist.get(position)); kimdenlist.remove(kimdenlist.get(position));

您可以称之为:

。

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