Question

I m试图取得以下产出:2_YEAR_912828SR2_20120514.dat 1337045684,并创建名词典,名称为关键值和日期

#get file attributes
datadict = {}

file_list_attr = sftp.listdir_attr()
for f in (file_list_attr): 
   fname = f.filename
   fdate = f.st_mtime

   print fname, fdate

2_YEAR_912828SR2_20120514.dat 1337045684

Answer 1

这里是一个工作例子,也关注数据转换(时间范围——日期);

from datetime import date

with open("file_with_data.txt", "r") as fl:
    datadict = dict([ (file_name, date.fromtimestamp(float(timestamp))
      for line in fl.readlines() for file_name, timestamp in line.split()])

Answer 2

如果您有<代码>f,作为具有这些特性的物体:

for f in (file_list_attr):
    datadict[f.filename] = f.st_mtime

That s taking your code as it is. But I think you have f as a string, so you would have to split it in two:

for f in (file_list_attr):
    filename, st_mtime = f.split(   , 2)
    datadict[filename] = st_mtime

Answer 3

dict((f.filename, f.st_mtime) for f in file_list_attr)

或 (didn t了解q)与空间有关的线路:

dict(f.split(   , 2) for f in file_list_attr)

Answer 4

Not knowing exactly what your code is.

data = {}
for file in file_list:
    data[f.filename] = f.st_mtime

Answer 5

Is not clear what you need, if you want to process the output of your code to create a dict you could make something like this:

output = """2_YEAR_912828SR2_20120514.dat 1337045684
2_YEAR_912828SR2_20120515.dat 1337045684
2_YEAR_912828SR2_20120516.dat 1337045684"""

result_dict = {}
for l in output.splitlines():
    k, v = l.split()
    result_dict[k] = v

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