Question

I m试图起草一个方案,从港口序列连接获取数据,并根据这些数据实时自动更新Tkinter窗口。

我试图为窗户建立一个单独的透镜,定期从主线上获取现有数据并更新窗户。

serialdata = []
data = True

class SensorThread(threading.Thread):
    def run(self):
        serial = serial.Serial( dev/tty.usbmodem1d11 , 9600)
        try:
            while True:
                serialdata.append(serial.readline())
        except KeyboardInterrupt:
            serial.close()
            exit()

class GuiThread(threading.Thread):
    def __init__(self):
        threading.Thread.__init__(self)
        self.root = Tk()
        self.lbl = Label(self.root, text="")

    def run(self):
        self.lbl(pack)
        self.lbl.after(1000, self.updateGUI)
        self.root.mainloop()

    def updateGUI(self):
        msg = "Data is True" if data else "Data is False"
        self.lbl["text"] = msg
        self.root.update()
        self.lbl.after(1000, self.updateGUI)

if __name == "__main__":
    SensorThread().start()
    GuiThread().start()

    try:
        while True:
            # A bunch of analysis that sets either data = True or data = False based on serialdata
    except KeyboardInterrupt:
        exit()

顺便说一句给我这个错误:

Exception in thread Thread-2: Traceback (most recent call last): File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/threading.py", line 522, in __bootstrap_inner self.run() File "analysis.py", line 52, in run self.lbl1.pack() File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/lib-tk/Tkinter.py", line 1764, in pack_configure + self._options(cnf, kw)) RuntimeError: main thread is not in main loop

当我看一看这一错误时,我多见有人试图从两条不同的路面与窗户互动的哨所,但我认为我没有这样做。任何想法? 感谢如此之多!

Answer 1

Don从一read开始,从主要过程开始。我把你的例子 into为表明这一原则的事例。

from time import sleep
import threading
from Tkinter import *

serialdata = []
data = True

class SensorThread(threading.Thread):
    def run(self):
        try:
            i = 0
            while True:
                serialdata.append("Hello %d" % i)
                i += 1
                sleep(1)
        except KeyboardInterrupt:
            exit()

class Gui(object):
    def __init__(self):
        self.root = Tk()
        self.lbl = Label(self.root, text="")
        self.updateGUI()
        self.readSensor()

    def run(self):
        self.lbl.pack()
        self.lbl.after(1000, self.updateGUI)
        self.root.mainloop()

    def updateGUI(self):
        msg = "Data is True" if data else "Data is False"
        self.lbl["text"] = msg
        self.root.update()
        self.lbl.after(1000, self.updateGUI)

    def readSensor(self):
        self.lbl["text"] = serialdata[-1]
        self.root.update()
        self.root.after(527, self.readSensor)

if __name__ == "__main__":
    SensorThread().start()
    Gui().run()

Answer 2

You need to put the GUI in the main thread, and use a separate thread to poll the serial port. When you read data off of the serial port you can push it onto a Queue object.

在总工会的校对中,你可以通过使用<条码>之后的<条码/代码”安排投票。要求履行排出电梯的功能,然后使用<>条码>,以有效地推展无限通道。

If the data that comes from the sensor comes at a fairly slow rate, and you can poll the serial port without blocking, you can do that all in the main thread -- instead of pushing and pulling from the queue, your main thread can just see if there s data available and read it if there is. You can only do this if it s possible to read without blocking, otherwise your GUI will freeze while it waits for data.

例如,你可以这样做:

def poll_serial_port(self):
    if serial.has_data():
        data = serial.readline()
        self.lbl.configure(text=data)
    self.after(100, self.poll_serial_port)

以上将检查每秒10次的序列港口,同时将一件物品从中删除。当然,你不得不根据实际数据条件作出调整。假设你有某种方法,如<代码>has_data,可以返回确实,而且只有经读赢得一只脚石。

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