我有一位词典,我想利用这些物品(钥匙,价值)产生单一方位,我将把这一论点转嫁给另一个关于指挥线的文字。
Snippet illustrates further:
args = { arg1 : 100, arg2 : 234 }
I want to create the string:
--arg1=100 --arg2=234
from the dictionary.
The naive (expensive) way to do that would be to loop through the items in the dictionary, building the string as I went along.
这样做有没有更长的征兆?
你们需要一种 lo,但你可以简明扼要地这样做:
" ".join("--%s=%s" % item for item in args.iteritems())
页: 1 2. 对第3条,改动<代码>teritems至>>项目
.join( --%s=%s % (k, v) for (k, v) in args.items())
既然你计划将其转至另一个文字,可能的话,使用<代码>subprocess。 模块: 不要 create!
args = [ /path/to/your/script ] + [ --%s=%s % item for item in args.iteritems()]
You can pass this array to subprocess.call() (or .Popen() etc.) and by not using an argument string you can ensure that even spaces, quotes, etc. won t cause any issues.
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