Question

我是新鲜的,可以与我的方案挂钩,并有一个问题。我必须从档案中获取销售信息,并以某种格式印刷。这是法典:

#Looping program to read file per line
for line in lines:
    # Formatting line to read later
    line = line.strip().split( , )
    year = line[0]
    year = int(year)
    month = line[1]
    month = int(month)
    day = line[2]
    day = int(day)
    linePoint = date(year, month, day)

    cost = line[3]
    cost = float(cost)

    #Finding the lines within the start and end date
    if (linePoint >= startDate) and (linePoint <= endDate):
        printcost = (cost / 100)
        printcost = int(printcost)

        print "%s.%s.%s" % (startYear, startMonth, startDay)
        print "0%s:" % printNum,  "*" * printcost

        newcost = newcost + cost
        printNum += 1

When I use the %s.%s.%s it s printing the date above the sales, I want it to print that above the other print statement once per month, and be able to increase it once the month is up. Also in the print "0%s:" % printNum, "*" * printcost statement I would like it to only print the zero for the first nine days.

从根本上讲,我的问题是,斯图尔如何在我操作一定次数的时间,但时间数取决于用户,并与日期相挂钩,因此,计算机需要能够识别日期。含糊不清。

Answer 1

如果您希望该产出成为<代码>01, 02 , ......, 10 , 11 , ......,那么你想要使用的形式是:

print "%02d" % printNum

至于在每个新月开始时(我如何阅读你所提问题第一部分),你可以做如下事情:

old_month = 0
for line in lines:
    # do stuff
    month = whatever...
    if month != old_month:
        # print header here
        old_month = month
    #rest of loop

Answer 2

我几乎肯定这是你想要的。 Note the “%02d” format specifier, which given You the leading 0, and theeck to see that the个月是否已经通过。

current_month, print_num, new_cost = None, 0, 0

for line in lines:
    fields = line.strip().split( , )
    year = int(fields[0])
    month = int(fields[1])
    day = int(fields[2])
    cost = float(fields[3])

    line_date = date(year, month, day)

    #Finding the lines within the start and end date
    if startDate <= line_date <= endDate:
        if month != current_month:
            print "%s.%s.%s" % (year, month, day)
            current_month = month

        print_cost = int(cost / 100)
        print "%02d: %s" % (print_num,  "*" * print_cost)

        new_cost += cost
        print_num += 1

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