I suggest to use a mapping of operator strings to corresponding functions:

operator_mapping = {
    "+": lambda x, y: x + y,
    "*": lambda x, y: x * y,
    "/": lambda x, y: x / y,
    "-": lambda x, y: x - y
}

之后,你可以利用:

operator_function = operator_mapping[operator_choice]

• 尽可能:

question = integerbox("What is " + str(number1) + " " + operator_choice + " " + str(number2) + " ?")

# Calculate the expected answer
expected_answer = operator_function(number1, number2)

# Check if the user s answer is correct
if question == expected_answer:
    print("Correct!")
else:
    print("Incorrect. The answer is", expected_answer)

遵循你想要达到的完全法典:

from random import randint
from easygui import buttonbox, integerbox

number1 = randint(1, 10)  
number2 = randint(1, 10)

operator_choice = buttonbox("What do you want your questions to be?", choices=["+", "*", "/", "-"])

# Mapping operator strings to corresponding functions
operator_mapping = {
    "+": lambda x, y: x + y,
    "*": lambda x, y: x * y,
    "/": lambda x, y: x / y,
    "-": lambda x, y: x - y
}

# Get the function corresponding to the selected operator
operator_function = operator_mapping[operator_choice]

# Construct the question
question = integerbox("What is " + str(number1) + " " + operator_choice + " " + str(number2) + " ?")

# Calculate the expected answer
expected_answer = operator_function(number1, number2)

# Check if the user s answer is correct
if question == expected_answer:
    print("Correct!")
    buttonbox("Correct")
else:
    print("Incorrect. The answer is", expected_answer)
    buttonbox("Try next one ...")

请注意,按照本法典的规定,我有点使用了从愤怒到扼杀的转换,然后又回到愤怒状态。

为使《守则》成为从1到10号基本业务的培训员,这一版本使得有可能在不需要重新启动的情况下继续实施,允许在不正确的情况下作出多重答复,并解决在结果不是仓促价值或负面的情况下,就划分和减员提出问题:

from random import randint
from easygui import buttonbox, integerbox, textbox

msgBoxSampleText =  "This is a sample text.
You can display multiple lines using the newline character."
msgBoxWindowTitle = "Sample Text Input Box"
#print ( textbox(msgBoxSampleText, msgBoxWindowTitle) )
#exit()

alternative_to_operator_mapping_using_lambda ="""
import operator
operator_mapping = {
     +  : operator.add,
     -  : operator.sub,
     *  : operator.mul,
     /  : operator.truediv,
     %  : operator.mod,
     **  : operator.pow,
     //  : operator.itruediv
}"""
# Mapping operator strings to corresponding functions
operator_mapping = {
    "+": lambda x, y: x + y,
    "*": lambda x, y: x * y,
    "/": lambda x, y: x / y,
    "-": lambda x, y: x - y
}
response = "Next one please ..."

while response == "Next one please ..." :

    operator_choice = buttonbox("What do you want your questions to be?", choices=["+", "*", "/", "-"], default_choice="+")
    if operator_choice is None :
        break

    # Get the function corresponding to the selected operator
    operator_function = operator_mapping[operator_choice]

    modulo = 1
    while modulo  != 0 : 
        number1 = randint(1, 10)  
        number2 = randint(1, 10)
        if operator_choice == "/":
            modulo = number1 % number2
        elif operator_choice == "-" :
            if number2 > number1: 
                modulo = 1
            else:
                modulo = 0
        else :  
            modulo = 0

    # Construct the question
    question = integerbox("What is " + str(number1) + " " + operator_choice + " " + str(number2) + " ?")

    # Calculate the expected answer
    expected_answer = operator_function(number1, number2)

    if question == expected_answer :
        print("Correct!")
        print( f"{response=}" )
    else:
        while question  != expected_answer  :
            print("Incorrect. The answer is", int(expected_answer))
            buttonbox("Try once again ...", choices=["OK"], default_choice="OK")
            question = integerbox("What is " + str(number1) + " " + operator_choice + " " + str(number2) + " ?")
    response = buttonbox("Correct", choices=["OK", "Next one please ..."], default_choice="Next one please ..." )

每个运营商在<代码>operator模块中都有功能等同。 例如,

from operator import add

assert add(3, 5) == 3 + 5

You can build a dictionary mapping strings to such functions.

ops = {"+": add}
assert ops["+"](3, 5) == 3 + 5