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使用Linux切割法将田地分成两个
原标题:splitting a field into two using linux cut
  • 时间:2012-05-21 15:44:53
  •  标签:
  • linux
  • cut

我在我的日志文件中有几个字段, 我用以下脚本将它们转换为 CSV 。

#!/bin/bash
INPUT=/home/MSC11/khanm/wwwp11dorganiser.co.uk_log
OUTPUT="/home/MSC11/khanm/output-$(basename $INPUT | cut -d .  -f1).csv"
# field names
s=1
ip=
dt=
method=
target=
protocol=
statuscode=
reference=
echo -n "Processing..."
# empty output file
>$OUTPUT
# read input line by line
while IFS= read -r line
do
   # get data
    ip=$(cut -d" " -f1<<<"$line")
    dt=$(cut -d" " -f4<<<"$line")
    method=$(cut -d" " -f6<<<"$line")
    target=$(cut -d" " -f7<<<"$line")
    protocol=$(cut -d" " -f8<<<"$line")
    statuscode=$(cut -d" " -f9<<<"$line")
    reference=$(cut -d" " -f11<<<"$line")
    # write cvs formatted output
    echo "${s},${ip},${dt},${target},${method},${protocol},${statuscode},${reference}" >>$OUTPUT
    # update counter
    s=$(( ++s ))
done < "$INPUT" 
echo "done."
echo "Total ${s} line processed and wrote to $OUTPUT cvs file."

变量“ dt” 是格式 29/ Nov/ 2007: 20: 42: 09 。 我想将其分为两个。 一个是格式 29/ Nov/ 2007 的日期, 第二个是格式 20: 42: 09 的日期。 我绕着剪切命令工作, 但我无法做到这一点。 感谢您的帮助 。

最佳回答
cut -d: -f1 <<< $dt
29/Nov/2007
cut -d: -f2- <<< $dt
20:42:09
问题回答

暂无回答




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