当调用tst 时,为何以下变量(A、B、C、D)没有变化?
A,B,C = 0,0,0
D = 0
def tst():
A,B,C = 1,2,3
D = 4
print(A,B,C,D)
tst() # tst is called
print(A,B,C,D)
Output:
(1, 2, 3, 4)
(0, 0, 0, 0)
当调用tst 时,为何以下变量(A、B、C、D)没有变化?
A,B,C = 0,0,0
D = 0
def tst():
A,B,C = 1,2,3
D = 4
print(A,B,C,D)
tst() # tst is called
print(A,B,C,D)
Output:
(1, 2, 3, 4)
(0, 0, 0, 0)
因为Python范围界定规则。
在 def tst () 中,您正在创建本地变量A、B和C, 并指定新的值。
如果您想要指定到全球 A、B和C 值,请使用全球关键字。
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tst
方法中的变量是 local ,也就是说,这些变量指的是该方法范围内存在的不同值。使用关键词global
(见global A,B,C,D
) (见st
) 中的关键词global A,B,C,D
(见 和问题