Question

我试图建立一个年目录结构, 包含代表月的子目录, 即月。

2012
- 01
- 02
- 03

我的代码是这样的:

newpath = "test"
for year in range(2000, 2013):
    for month in range(1, 13):
        newpath += str(year)+ \ +str(month)
        if not os.path.exists(newpath):
            os.makedirs(newpath)

我搞错了

OSError: [Errno 2] No such file or directory:  test\2000\1

Would someone please have some information on this Thank you

Answer 1

str(1) return 1 , not >01 . do "%02d"% month .

(考虑使用 os.path.join 构建路径字符串。 )

Answer 2

newpath += str(year)+ \ +str(month)

在每个迭代中将新字符附加到同一个字符串上,这不是你想要的。

尝试此 :

root_path = "test"
for year in range(2000, 2013):
    for month in range(1, 13):
        newpath = os.path.join(root_path,  {0:04} .format(year),  {0:02} .format(month))
        if not os.path.exists(newpath):
            os.makedirs(newpath)

os.path.join 将在您的 OS 上正确构建路径名。

Answer 3

您的 > newpath 将会是

test200012000220003200042000520006200072000820009200010200011200012200112001220013200142001520016200172001820019200110200111200112200212002220023200242002520026200272002820029200210200211200212200312003220033200342003520036200372003820039200310200311200312200412004220043200442004520046200472004820049200410200411200412200512005220053200542005520056200572005820059200510200511200512200612006220063200642006520066200672006820069200610200611200612200712007220073200742007520076200772007820079200710200711200712200812008220083200842008520086200872008820089200810200811200812200912009220093200942009520096200972009820099200910200911200912201012010220103201042010520106201072010820109201010201011201012201112011220113201142011520116201172011820119201110201111201112201212012220123201242012520126201272012820129201210201211201212

在您上次迭代中。您不需要附加到 newpath 。

Answer 4

您没有在循环中重设 newpath 。类似的东西应该效果更好 :

for year in range(2000, 2013):
    for month in range(1,13):
        newpath = os.path.join("test", str(year), "%02d"%(month,)
        if not os.path.exists(newpath):
            os.makedirs(newpath)

友情链接