Question

for (i = 0; i < n; i++)
    {
        x[i] = (float) (i * step);
        k = 5;
        sum = 0;
        while(k > 0)
        {
            sum = sum + (1/k) * sin((k*PI*x[i])/5);
            k = k - 2;
        }
        y1[i] = (4/PI)*sum;

        y2[i] = 0*(4/PI)*sin((PI*x[i])/5);
    }

当对除 1 以外的每个 k 值进行调试时, 当总和显示等于 0 时, 我是否正确执行回路?

内容1:

int k;
double sum;

Answer 1

由于 1 和 k 是 ints -- 1/ k 是 < engreena href=" http:// mathworld. wolfram. com/ Integer Division. html" rel = " norefererr" > integer division < / a/ enterger >, 如果 k> 1, 则其总是 0 。因此, 没有添加任何内容来加和。您想要 1/ k 来执行浮动点分割。请尝试 < code> 1. 0/ k < / code > 而不是 1/ k 。

Answer 2

1/k will give 0. Since it is Integer Division. You will have to give 1.0/k or 1/(float)k

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