Question

是否有更明智的方法来做到这一点? 我想通过对许多其他列表的索引进行总结来做一个新的列表。我对编程相当新,这似乎是一个非常笨拙的方法!

list1 = [1,2,3,4,5]
list2 = [1,1,1,4,1]
list3 = [1,22,3,1,5]
list4 = [1,2,5,4,5]
...
list100 = [4,5,6,7,8]

i = 0
while i < len(list1):
    mynewlist[i] = list1[i]+list2[i]+list3[i]+list4[i]+...list100[i]
    i = i+1

Answer 1

这对zip 来说是一个非常有用的例子。

>>> list1 = [1,2,3,4,5]
>>> list2 = [1,1,1,4,1]
>>> list3 = [1,22,3,1,5]
>>> list4 = [1,2,5,4,5]
>>> [sum(x) for x in zip(list1, list2, list3, list4)]
[4, 27, 12, 13, 16]

或者,如果将数据作为清单而不是单独清单列出:

>>> data = [[1,2,3,4,5], [1,1,1,4,1], [1,22,3,1,5], [1,2,5,4,5]]
>>> [sum(x) for x in zip(*data)]
[4, 27, 12, 13, 16]

同样,如果将数据存储为列表的dict > >,您可以使用 _itervalues" rel="nofollown"_code>dict.values () 来检索列表值,并以类似的方式使用 :

>>> data = {"a":[1,2,3], "b":[3,4,4]}
>>> [sum(x) for x in zip(*data.itervalues())]
[4, 6, 7]

请注意,如果列表的长度不均, zip 将一直工作到最短的列表长度。例如 :

>>> data = [[1,2,3,4,5], [1,1], [1,22], [1,2,5]]
>>> [sum(x) for x in zip(*data)]
[4, 27]

如果您想要获得包含所有数据的结果, 您可以使用 < a href=" http://docs. python.org/library/itertools.html#itertools.izip_longest" rel="nofollow"\code>etertools.izip_longest (配有适当的 fille )。例如 :

>>> data = [[1,2,3,4,5], [1,1], [1,22], [1,2,5]]
>>> [sum(x) for x in izip_longest(*data, fillvalue=0)]
[4, 27, 8, 4, 5]

Answer 2

@Shawns 答对了, 我认为map 可能比列表理解更优雅:

>>> list1 = [1,2,3,4,5]
>>> list2 = [1,1,1,4,1]
>>> list3 = [1,22,3,1,5]
>>> list4 = [1,2,5,4,5]
>>> map(sum, zip(list1, list2, list3, list4))
[4, 27, 12, 13, 16]

Answer 3

首先的问题是: 您的代码中不应该有 100 个变量。

list1 = [1,2,3,4,5]
list2 = [1,1,1,4,1]
list3 = [1,22,3,1,5]
list4 = [1,2,5,4,5]
...
list100 = [4,5,6,7,8]

相反,你应该有类似

list_of_lists = []
list_of_lists.append([1,2,3,4,5])
list_of_lists.append([1,1,1,4,1])
list_of_lists.append([1,22,3,1,5])
list_of_lists.append([1,2,5,4,5])
...

然后您计算出想要的结果 :

[sum(x) for x in zip(*list_of_lists)]

Answer 4

您真的需要阅读 Python 教程。

sum(list1) will give you the sum of that list.
You need to learn about for loops
Your lists should themselves be stored in a list

旋转列表集的方式是使用 zip :

list1 = [1,2,3,4,5]
list2 = [1,1,1,4,1]
list3 = [1,22,3,1,5]
zip(list1,list2,list3)
# matches up element n of each list with element n of the other lists
#=> [(1, 1, 1), (2, 1, 22), (3, 1, 3), (4, 4, 1), (5, 1, 5)]
# now you want to add up each of those tuples:
[sum(t) for t in zip(list1,list2,list3)]
#=> [3, 25, 7, 9, 11]

要使用 zip 这样的列表列表工作,请查看 etertools 模块,或学习 args 语法。

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