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NSBundule 实例方法 URL URL URL URL 资源资源: 设备上返回无效 CFStringRef 的扩展返回无效 CFStringRef
原标题:NSBundle instance method URLForResource:withExtension returning invalid CFStringRef on device

我在我的代码中使用以下方法:

NSURL *modelURL = [[NSBundle mainBundle] URLForResource:@"myappname" withExtension:@"momd"];

当我在模拟器上运行时, 这返回一个工作 NSURL。 当我运行我的设备时, 它返回一个无效的 CFSTringRef。 我做错了什么?

Another related question, my xcode project file is named like this: "MyApp", and the end of my bundle identifier is named like this: "myapp".

我尝试过两种方法,结果都一样,但我读过资源参数字符串对案件敏感。我应该使用哪一种?

最佳回答

尝试 :

NSString *modelPath = [[NSBundle mainBundle] pathForResource:@"YourModelName" ofType:@"momd"];
NSManagedObjectModel *objectModel = [[NSManagedObjectModel alloc] initWithContentsOfURL:[NSURL fileURLWithPath:modelPath]];
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