我手上有那根发光的弦
TOKEN a$dmin
我想从中提取值 < code> a$dmin 。
re.findall("(?i)TOKEN (.*)",string)
but what I m getting is a$dmin
我如何正确做到这一点?
我手上有那根发光的弦
TOKEN a$dmin
我想从中提取值 < code> a$dmin 。
re.findall("(?i)TOKEN (.*)",string)
but what I m getting is a$dmin
我如何正确做到这一点?
与 str.strip
匹配 :
re.findall(r"(?i)TOKEN (S*)", s.strip())
或修改表达式以只匹配非空格:
re.findall(r"(?i)TOKEN (S*)", s)
如果你有字面上的鞭笞,例如:
s = r TOKEN a$dmin
使用此表达式来匹配第一个斜线之前的所有表达式 :
re.findall(r"(?i)TOKEN (.*?)\", s)
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