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How should I use servlets and Ajax? (8 answers)

Closed 6 years ago.

i am sending 2 data to the servlet through ajax from jsp and the servlet just get those data, then convert to json obj and return that json. now the jsp get that json to show those 2 data. ajax is successfully executing the servlet but everytime is alerts me the error not the success. pls tell me what should i do to display those data in alert? details.jsp:

<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>            
    function doajax(){
        $.ajax({
            url: "AccountDetails",
            type: "post",
            dataType: "json",
            data: { "mobileNo":"01914752849", "fullName":"Md. Muzahid-ul Islam" },
            error:function(){
                alert("error occured!!!");
            },
            success:function(data){
                alert(data.fullName + "
" + data.mobileNo);
            }
         });
      }
</script>

账户 Details.java( 服务器) :

PrintWriter out = response.getWriter();
try {
    String fullName = request.getParameter("fullName");
    String mobileNo = request.getParameter("mobileNo");
    JSONObject jsonObject = new JSONObject();
    jsonObject.put("fullName", fullName);
    jsonObject.put("mobileNo", mobileNo);
    out.println(jsonObject);
} finally {
    out.flush();
    out.close();
}

Answer 1

编辑服务器中的代码到

Gson gson = new Gson();
JsonElement element = gson.toJsonTree(<Object_to_be_passed or model_class>);
out.write(element.toString());

而且您还必须在服务器中导入两个包 com.google.gson.Gson 和 com.google.gson.JsonEplement

注意: 尝试通过在模型类中包装数据来转发数据

希望它能有所帮助..) :)

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