Question

我是一个新来的对阵队。

我试图根据一本关于Jjango的书做一个样本

我在我的模范课程中加上了“阶级管理者”, 然而,在对角行政界面中, 我只能看到“用户”、“群体”和“特选人”, 我的模范课程都没有出现。

没有任何错误或警告信息,所以我不知道发生了什么,我下一步该怎么办。

有帮助吗?

from django.db import models

# Create your models here.
class Publisher(models.Model):
    name = models.CharField(max_length=30)
    address=models.CharField(max_length=50)
    city=models.CharField(max_length=60)
    state_province=models.CharField(max_length=30)
    country=models.CharField(max_length=50)
    website=models.URLField()

    def __str__(self):
        return self.name

    class Admin:
        pass

class Author(models.Model):
    salutation=models.CharField(max_length=10)
    first_name = models.CharField(max_length=30)
    last_name = models.CharField(max_length=40)
    email=models.EmailField()
    headshot=models.ImageField(upload_to= /tmp )

    def __str__(self):
        return  %s %s  % (self.first_name, self.last_name)

    class Admin:
        pass

class Book(models.Model):
    title=models.CharField(max_length=10)
    authors=models.ManyToManyField(Author)
    publisher=models.ForeignKey(Publisher)
    publication_date = models.DateField()

    def __str__(self):
        return self.title

Answer 1

您需要做三件事才能通过管理网站编辑您的模型 :

在您的应用程序目录中以代码创建文件管理员. py (参见 < a href="https://docs.djangoproject.com/en/dev/ref/contrib/admin/#modadmin-objects" rel="nofollow" >https://docs.djangoproject.com/en/dev/ref/contrib/admin/#modadmin-objects ) 创建文件管理员:
```
from django.contrib import admin
from your_app.models import Publisher, Author, Book

admin.site.register(Author)
admin.site.register(Publisher)
admin.site.register(Book)
```
在您的 urls.py 中添加以下内容 (请看< a href="https://docs.djangoproject.com/en/dev/ref/contrib/admin/#hooking-adminsite-instations-into-your-urlconf" rel=“nofollow" >https://docs.djangoproject.com/en/dev/ref/contrib/admin/#hooking-adminsite-adminsite-intances-inst-into-your-urconf < /a > :
```
from django.conf.urls import patterns, url, include
from django.contrib import admin

admin.autodiscover()

urlpatterns = patterns(  ,
    (r ^admin/ , include(admin.site.urls)),
    # your urls goes here
)
```

请确定您设置的. py 符合以下条件 (请看< a href="https://docs.djangoproject.com/en/dev/ref/contrib/admin/#overview>https://docs.djangoproject.com/en/dev/ref/contrib/admin/#overview ):

TEMPLATE_CONTEXT_PROCESSORS = (
     django.contrib.messages.context_processors.messages ,
    #other context processors
)

MIDDLEWARE_CLASSES = (
     django.contrib.messages.middleware.MessageMiddleware ,
    # other middleware
)

INSTALLED_APPS = (
     django.contrib.admin ,
     django.contrib.auth ,
     django.contrib.contenttypes ,
     django.contrib.messages ,
     django.contrib.sessions ,
    # other apps
)

Answer 2

您应该创建管理员. py, 并遵循以下代码

from xxxxx.models import Publisher
from django.contrib import admin

admin.site.register(Publisher)
admin.site.register(Author)
admin.site.register(Book)

Answer 3

你错过了有关“https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin' rel=“nofollow'>在行政网站注册模型的部分。

Answer 4

您没有这样做。正确的方法是在 < code> models. py 和 admin. py 中设置模型。

models. py :

from django.db import models

# Create your models here.
class Publisher(models.Model):
    name = models.CharField(max_length=30)
    address=models.CharField(max_length=50)
    city=models.CharField(max_length=60)
    state_province=models.CharField(max_length=30)
    country=models.CharField(max_length=50)
    website=models.URLField()

    def __str__(self):
        return self.name


class Author(models.Model):
    salutation=models.CharField(max_length=10)
    first_name = models.CharField(max_length=30)
    last_name = models.CharField(max_length=40)
    email=models.EmailField()
    headshot=models.ImageField(upload_to= /tmp )

    def __str__(self):
        return  %s %s  % (self.first_name, self.last_name)


class Book(models.Model):
    title=models.CharField(max_length=10)
    authors=models.ManyToManyField(Author)
    publisher=models.ForeignKey(Publisher)
    publication_date = models.DateField()

    def __str__(self):
        return self.title

admin.py :

from django.contrib import admin
from myproject.myapp.models import Author, Publisher


class AuthorAdmin(admin.ModelAdmin):
    pass


class PublisherAdmin(admin.ModelAdmin):
    pass


admin.site.register(Author, AuthorAdmin)
admin.site.register(Publisher, PublisherAdmin)

此外,如果您的行政课程空空如也,只要有 pass ,您就可以一起省略,所以最终会变成这样:

admin.py :

from django.contrib import admin
from myproject.myapp.models import Author, Publisher


admin.site.register(Author)
admin.site.register(Publisher)

Answer 5

You re using old methods to declare models which should appear in admin interface. This methods are obsolete now. Please consider to manuals and make yourself clear of which version of django you use. And how to get what you want.

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