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我如何用网格.arrange来安排一个可变的地块列表?
原标题:How do I arrange a variable list of plots using grid.arrange?
  • 时间:2012-05-22 17:08:08
  •  标签:
  • r
  • ggplot2
library(ggplot2)
df <- data.frame(x=1:10, y=rnorm(10))
p1 <- ggplot(df, aes(x,y)) + geom_point()
plist <- list(p1,p1,p1,p1,p1)
# In my real example,a plot function will fit a ggplot to a list of datasets 
#and return a list of ggplots like the example above.

我想用 grid.arrange () gridExtra 中安排地块。

如果 plist 中的地块数量是变量, 我将怎么做?

This works: grid.arrange(plist[[1]],plist[[2]],plist[[3]],plist[[4]],plist[[5]])

但我需要一个更普遍的解决方案。 想法呢?

最佳回答

不如这样:

library(gridExtra)
n <- length(plist)
nCol <- floor(sqrt(n))
do.call("grid.arrange", c(plist, ncol=nCol))

""https://i.sstatic.net/Rt0qB.png" alt="此处输入图像描述"/ >

问题回答

您可以使用 grid.arrange () arrangeGrob () 列表,只要您在每个函数中使用 grobs {/code> 参数指定列表。 例如,在您给出的示例中:

library(ggplot2)
library(gridExtra)
df <- data.frame(x=1:10, y=rnorm(10))
p1 <- ggplot(df, aes(x,y)) + geom_point()
plist <- list(p1,p1,p1,p1,p1)

grid.arrange(grobs = plist, ncol = 2) ## display plot
ggsave(file = OutFileName, arrangeGrob(grobs = plist, ncol = 2))  ## save plot

要在一页上设置所有绘图, 您可以计算这样的列数和行数 :

x = length(plots)

cols = round(sqrt(x),0)
rows = ceiling(x/cols)

由于大多数多个绘图函数都有 ncol 和 nrow 作为参数, 您可以把这些放进去。 我喜欢从 ggpubr 中绘制 。

ggarrange(plotlist = plots, ncol=cols, nrow = rows)

这有利于比列多的行, 而不是列, 如果您想要相反的话, 则会反转。 也就是说, 6个地块, 它会给3个行和2个列, 而不是相反方向 。





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