Question

我被一个问题缠住了!

我和JSON有个弦像:

{"用户名":"用户名","PassWord":"密码"}

我用X代码构建这根JSON字符串,比如:

 NSMutableDictionary *jsonDict = [[NSMutableDictionary alloc] init];
     [jsonDict setValue:self.usernameField.text forKey:@"UserName"];
     [jsonDict setValue:self.passwordField.text forKey:@"PassWord"];
     NSLog(@"Dict: %@",jsonDict);

     NSData *jsonData = [NSJSONSerialization dataWithJSONObject:jsonDict options:kNilOptions error:nil];
     NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
     NSLog(@"JSON String: %@",jsonString);

     NSString *postStr = [NSString stringWithFormat:@"%@",jsonString];

但我现在想和JSON一起唱一首...

{ "comp": [
  { "id": "1" },
  { "id": "2" },
  { "id": "3" }
 ],
"contact": [
  { "mail": "[email protected]", "name": "Name"  },
  { "mail": "[email protected]", "name": "Name"  }
 ]
}

但我怎么做有人能帮我吗

Answer 1

这将给予您计算。使用您所拥有的和这个示例, 您应该能够很容易地获得联系。

NSDictionary *id1 = [NSDictionary dictionaryWithObjectsAndKeys:
                       @"1", "id", nil];
NSDictionary *id2 = [NSDictionary dictionaryWithObjectsAndKeys:
                       @"2", "id", nil];
NSDictionary *id3 = [NSDictionary dictionaryWithObjectsAndKeys:
                       @"3", "id", nil];

NSArray *ids = [NSArray arrayWithObjects:id1, id2, id3, nil];

NSDictionary *comp = [NSDictionary dictionaryWithObjectsAndKeys:ids, @"comp", nil];

Also, check out the following library for easy serialization/deserialization. JSONKit

友情链接