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我怎样以白金星的数数来计算呢?
原标题:How do i compute with (numpy) -arrays eloquently in python
  • 时间:2012-05-24 15:32:11
  •  标签:
  • python
  • loops

我怎样才能以更有效的方式表达这一结构呢?

x = [2, 4, 6, 8, 10]
for p in x:
   x = x/2
print x

必须有一个很好的方法来做到这一点。

最佳回答

如果您试图将 >x 的每一个元素除以 2 , 那么以下单位会这样做 :

x = np.array([2, 4, 6, 8, 10])
x /= 2

产生的 >x 值为 arary([1、2、3、4、5])

请注意以上使用整数( 整数) 。 如果您想要浮动点分隔, 请将 < code> x 设置为浮动点数组 :

x = np.array([2, 4, 6, 8, 10], dtype= float64 )

或将区域更改为:

x = x / 2.0
问题回答

如果是一个缩水数组, 您可以同时完成全部任务 :

In [4]: from numpy import array

In [5]: x = array([2, 4, 6, 8, 10])

In [6]: print x/2
[1 2 3 4 5]




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