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如何制造支管 将雷诺假象中的所有呼声 抛出例外?
原标题:How to create stub, that throws exception on all calls in Rhino mocks?

有没有可能和Rhino Mocks一起制造一个把所有电话都排除在外的支管?

public interface IMyIF
{
    // Some methods
}

[TestClass]
public class MyTestClass
{
    [TestMethod()]
    public void MyTest()
    {
        MockRepository mocks = new MockRepository();
        IMyIF stb = mocks.Stub<IMyIF>();

        // Somehow set stb to throw some exception on every method call
        // without knowing all the methods and overloads in IMyIF interface

        // use stb to test something
    }
}
最佳回答
var stb = MockRepository.GenerateStrictMock<IMyIF>();
问题回答

非常奇怪的要求。 您想要测试什么? 如果您正在测试界面 < code> bar 的 < code > 方法 < iFoo < /code >, 测试类中调用该方法时会有一些例外, 那么您只需在方法栏上设置此期望。 不要同时测试所有方法 。

这将集中测试一个特定的交互作用, 介于 sut 和 依附关系之间( 我走这条路):

var mock = MockRepository.GenerateMock<IMyIF>();
mock.Expect(m => m.Foo()).Throw(new MyCustomException());
sut.Exercise(mock);

这将抛出预期风险例外 :

var mock = MockRepository.GenerateStrictMock<IMyIF>();
sut.Exercise(mock);

这将抛出 Null reference 例外 :

sut.Exercise(null);

您也可以创建从 IMyIF 继承的类 < code> MyIFStub 。 右键点击界面名称并选择 < em> imyIF 界面 < / em> 。 视觉工作室将生成界面的子床成员, 这将丢弃非执行例外 。 如果您需要的话, 您可以更改缓冲执行 :

public class MyIFStub : IMyIF
{    
    public void Foo()
    {
       throw new NotImplementedException();
    }

    // other members
}




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