Question

这是我的代码来得到Json的响应字符串

使用这个方法我就能拿到这个字符串

NSDictionary *selector = [json valueForKey: @"Title"];
NSMutableArray *dictArray = [[NSMutableArray alloc] initWithObjects: selector,nil];
str1=[[dictArray objectAtIndex:i] valueForKey:@"CompanyName"];

打印“str1”

我正得到

(
    "[email protected]"
),
    (
    "[email protected]",
    "[email protected]"
),
    (
    "[email protected]"
),
    (
    "[email protected]"
),
    (
    "[email protected]"
),
    (
    "[email protected]"
),
    (
    "[email protected]"
),
    (
    "[email protected]"
)

)

我试图通过使用“ ” 操作员来存储阵列

像这样

NSArray *SplitStringArray = [str1 componentsSeparatedByString:@", "];

但我没有把字符串分成一系列元素

谁能帮我一下吗?

Answer 1

    NSDictionary *selector = [json valueForKey: @"Title"];

    NSMutableArray *dictArray = [[NSMutableArray alloc] initWithObjects: selector,nil];

    NSMutableArray *str1Array=[[dictArray objectAtIndex:i] valueForKey:@"CompanyName"];


        //note this line
    NSMutableArray *SplitStringArray =[[NSMutableArray alloc]init];

    for (id eachArray in str1Array) {


        if ([eachArray count]>0) {


            for (int i = 0; i<[eachArray count]; i++) {

                NSString *emailid=[NSString stringWithFormat:@"%@",[eachArray objectAtIndex:i]];

                [SplitStringArray addObject:emailid];


            }

        }

    }

    NSLog(@"SplitStringArray : %@",SplitStringArray);

Answer 2

NSMutableArray *SplitStringArray = [[NSMutableArray alloc]init]; 
[SplitStringArray setArray:[str1 componentsSeparatedByString:@","]];

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