Question

看起来像这个文件 :

BURGER KING
BRG
MCDONALDS
MCDNLDS
WENDYS
WNDY

示例:

food( abbreviations.txt )

Enter a fast food place: McDonalds

Abbreviation: MCDNLDS

Enter a fast food place:

Thank you!

到目前为止:

infile = open(filename,  r )

l = infile.readlines()

infile.close()

但我不知道在读行之后该怎么办

Answer 1

我不该这么做但我觉得运动很滑稽

lines = [i.strip() for i in l if i.strip()]
abbrev = dict(zip(lines[0::2], lines[1::2]))

然后abbrev 是一个字典/绘图,您通过将整个名字作为密钥查找获得缩略语。

如果你想听懂我的话我建议你用互动的 Python 贝壳分别试试每一块

Edit for lazy StackOverflow readers

在此交互式会议示例中,还提出一些补充建议:

>>> infile = open("abbreviations.txt", "r")
>>> lines = [l.strip() for l in infile]
>>> lines
[ BURGER KING ,   ,  BRG ,   ,  MCDONALDS ,   ,  MCDNLDS ,   ,  WENDYS ,   ,  WNDY ]
>>> lines[0::4]
[ BURGER KING ,  MCDONALDS ,  WENDYS ]
>>> lines[2::4]
[ BRG ,  MCDNLDS ,  WNDY ]
>>> zip(lines[0::4], lines[2::4])
[( BURGER KING ,  BRG ), ( MCDONALDS ,  MCDNLDS ), ( WENDYS ,  WNDY )]
>>> abbrev = dict(zip(lines[0::4], lines[2::4]))
>>> abbrev
{ MCDONALDS :  MCDNLDS ,  WENDYS :  WNDY ,  BURGER KING :  BRG }
>>> abbrev["WENDYS"]
 WNDY

Answer 2

您可以用对子阅读行, 并分别将其键和值制成以添加到字典中。然后获得用户输入( 在循环中) 并查看该插图中输入的字符串。

Answer 3

开始 :

name_map = {}
last_line = False
for line in file.readlines():
    line = line.strip()

    if not line:
        # Blank line
        continue

    if not last_line:
        last_line = line
    else:
        name_map[last_line] = line
        last_line = False

真的,你应该使用类似的东西,“http://www.json.org/'rel=“nofollow”>Json 。

Edit for lazy StackOverflow readers

友情链接