Question:

Question

Question:

Details:

我正在查询文件权限喜欢这样 :

statInfo = os.stat
permissions = stat.S_IMODE ( os.stat (  fooBar.txt  ).st_mode )

返回小数格式的允许值。因此, 如果 < code> fooBar. txt 有八进制文件权限 < code> > 0700 , 这里 < code > permissions 设置为小数值 < code> < 448 。我要为每个权限设定9个变量( 所有人Read , < code> > 所有人Wright , < code > < 所有人Execut , < code>, < group>Read ) 。 ) 如果我要这样做, 我就会使用这样的粗力方法 :

statInfo = os.stat
permissions = stat.S_IMODE ( os.stat (  fooBar.txt  ).st_mode )
octPermissions = oct ( permissions )

ownerRead = octPermissions [1] >= 4
ownerWrite = octPermissions [1] == 2 or octPermissions [1] == 6 or octPermissions [1] == 3 or 
ownerExecute = octPermissions [1] == 1 or octPermissions [1] == 5 or octPermissions [1] == 3

是否有一种更有效的方法来做到这一点而不必转换为八溴二苯醚,因为这个函数将被称作相当小的函数吗?

Answer 1

您可以使用比特和运算符 :

m = os.stat( fooBar.txt ).st_mode
otherExec  = bool(m & 0001)
otherWrite = bool(m & 0002)
otherRead  = bool(m & 0004)
groupExec  = bool(m & 0010)
groupWrite = bool(m & 0020)
groupRead  = bool(m & 0040)
...

Answer 2

使用“bitwith”和“stat 模块 :

import stat
import os

mode = os.stat( fooBar.txt ).st_mode

otherRead  = bool(mode & stat.S_IROTH)
otherWrite = bool(mode & stat.S_IWOTH)
otherExec  = bool(mode & stat.S_IXOTH)
...

更易读

Answer 3

我将它合并成一个功能得到UNIX的许可:

import os
from stat import (S_IRUSR, S_IWUSR, S_IXUSR, S_IRGRP, S_IWGRP,
                  S_IXGRP, S_IROTH, S_IWOTH, S_IXOTH)

def bit2int(bit):
    return int(oct(bit))

def convert_st_mode(st_mode):
    bits = (S_IRUSR, S_IWUSR, S_IXUSR, S_IRGRP, S_IWGRP, S_IXGRP,
            S_IROTH, S_IWOTH, S_IXOTH)
    mode = "%03d" % sum(int(bool(st_mode & bit)) * bit2int(bit) for bit in bits)
    return mode

def get_unix_permissions(pth):
    mode = convert_st_mode(os.stat(pth).st_mode)
    return mode

用法 :

mode = get_unix_permissions("somefile")
print(mode)

Question:

Details:

友情链接