假设我有一个目录上有一堆文件, 有不同的扩展名:
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我想创建一个小脚本,将每个文件重命名为格式 mystring_x.ext ,其中 mystring 是我在脚本中设置的字符串, x 是正在重新命名的文件的编号,而 ext 将是文件的
我理解我应该使用 os 模块重命名文件,但我应该尝试和采用什么程序来完成这项任务?
directory = /path/to/dir
base = mystring
for i, f in enumerate(os.listdir(directory), 1):
ext = f.rsplit( . , 1)[-1]
absolutify = lambda s: os.path.join(directory, s)
os.rename(absolutify(f), absolutify( %s_%d.%s % (base, i, ext)))
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