我试图使用 noumpy.loadttxt 来读取文件里的数据, 这个文件看起来像 :
## 14 line of header
3 0 36373.7641026
3 1 36373.7641026
3 2 36373.7641026
...
当我给它这个:
>>> chunk, power = numpy.loadtxt(bf,skiprows=14,usecols=(1,2),unpack=True)
或甚至这样:
>>> power = numpy.loadtxt(bf,skiprows=14,usecols=(2))
它说, < code> TypeError: 内在对象不是可替换的
我以为是因为前两列的整数不是浮的,但现在我甚至不确定它指的是哪个内号,因为它甚至不会只读到浮点数。我如何使 loadtxt 工作?
相关 : 我如何用 < code> dtype =? I 无法通过 Google 找到多个列的格式 。
在您的第二个示例中,问题可能是 usecols=(2) 。 usecols 必须是一个序列。 (2) 是整数2,而不是包含2的单元素图普,并且很可能是错误信息所抱怨的错误信息: loadtxt () 正试图在 unt 上插入。使用 (2) (或 [2] )。
很难知道在本案中是什么导致了问题,因为你没有给我们足够的信息。鉴于你在这里张贴的信息,你的代码应该起作用:
>>> with open( beamtest.out , r ) as f:
... f.readlines()
...
[ header 0
, header 1
, header 2
, header 3
, header 4
,
header 5
, header 6
, header 7
, header 8
, header 9
,
header 10
, header 11
, header 12
, header 13
,
3 0 36373.7641026
, 3 1 36373.7641026
, 3 2 36373.7641026 ]
>>> chunk, power = numpy.loadtxt( beamtest.out , skiprows=14,
usecols=(1,2), unpack=True)
>>> chunk
array([ 0., 1., 2.])
>>> power
array([ 36373.7641026, 36373.7641026, 36373.7641026])
当然,正如usecols 不接受单整数;它(1) 只是括号中的 1 ;要创建一个tuple,你需要在那里有一个逗号 -- (1) 。
下面是如何使用 dtype 来指定多列格式的示例 :
>>> record = numpy.loadtxt( beamtest.out , skiprows=14, usecols=(1, 2),
dtype={ names :( chunk , power ),
formats :( i8 , f8 )})
>>> record
array([(0, 36373.7641026), (1, 36373.7641026), (2, 36373.7641026)],
dtype=[( chunk , <i8 ), ( power , <f8 )])
>>> record[ chunk ]
array([0, 1, 2])
>>> record[ power ]
array([ 36373.7641026, 36373.7641026, 36373.7641026])
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