我试图从使用Regex的一连串文本中获取电子邮件地址。
demo_text = """hsds hjdsjd ksdkj
Reason: 550 [email protected]... No such user
sdhjsdjh
"""
# the following code extracts the whole line "Reason: 550 [email protected]... No such user"
# how do I just extract "[email protected]"?
email = re.search("Reason: 550 (.+)... No such user", demo_text).group(0)
.group(0) 返回整个字符串。 您想要 . group(1) :
email = re.search("Reason: 550 (.*?)... No such user", demo_text).group(1)
取第1组。
....group(1)
较一般性的正征解决办法是:
r"[w.]+@[w.]+"
仅使用 :
email_id = re.search(r ([w.])+@([w.])+ , demo_text)
email_id.group(1) # the username part
email_id.group(2) # the host part
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