library(gplots)
shades= c(seq(-1,0.8,length=64),seq(0.8,1.2,length=64),seq(1.2,3,length=64))
heatmap.2(cor_mat, dendrogram= none , Rowv=FALSE, Colv=FALSE, col=redblue(64),
breaks=shades, key=TRUE, cexCol=0.7, cexRow=1, keysize=1)
休息有些问题,希望得到帮助。
运行代码后我收到错误信息
Error in image.default(1:nc, 1:nr, x, xlim = 0.5 + c(0, nc), ylim = 0.5 + : must have one more break than colour
感谢您的时间和体谅。
嗯,我们没有cor_mat,所以我们无法自己尝试,但问题似乎在于锡上写的是什么,不是吗?热映射(以及基于图像的所有函数)如何与断开器和颜色矢量一起工作,是断开符定义了数据矩阵值变化意味着颜色变化的点。简言之,如果break = c(1,2,3) ,以及您的 col = c("红色","蓝色") :
您的代码中正在继续的是,用阴影为 break 提供了长度 3*64 矢量到 break ,而 redbluue(64) 只给你64种颜色。尝试用 redblue(64) 替换 redblue(64) , 例如 < code> redblue(3*64-1) 。
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